В WPF DataGrid поддерживает данную функциональность, и, к счастью, она .... Row="2" />

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I have a WPF DataGrid … I have the click event handler as: … How do I get the row on which the Context Menu was before the click?

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Mar 29, 2017 ... This topic describes the styles and templates for the DataGrid control. You can ... The DataGridRow element does not have any named parts.

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13 окт 2013 ... Row="0" VerticalAlignment="Top" Width="1152" Name="MainDataGrid" ... Resources>

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I have a datagrid that potentially can have many rows. As the user right clicks one of the rows, I need to show a context menu for each of the rows and perform an action...

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... ContextMenuStrip strip = new ContextMenuStrip(); foreach ( DataGridViewColumn column in dataGridView.Columns) ... Rows[ mouseLocation.RowIndex] .

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22 июл 2009 ... If you expand the DataGrid ControlTemplate you can see that there is a Button which is ... xmlns:toolkit="http://schemas.microsoft.com/wpf/2008/toolkit" .... Row=" 1" CanContentScroll="{TemplateBinding CanContentScroll}" ...

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Represents a row. ... public class DataGridRow : System. ...... из своей реализации ArrangeCore(Rect) (или эквивалента уровня инфраструктуры WPF) для ...

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The WPF Menu control · The WPF ContextMenu · The WPF ToolBar control · The WPF ... The DataGrid control · DataGrid columns · DataGrid with row details ...

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The WPF Menu control · The WPF ContextMenu · The WPF ToolBar control · The WPF ... The DataGrid control · DataGrid columns · DataGrid with row details ...

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Hi There I am beginner programmer and new to WPF and have a simple question, but I have spent quite some time searching it a could not figure it out, so I hope you guys will help me.

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7 фев 2016 ... Обзор механизма привязки (binding) в WPF, класс Binding и его основные свойства и методы, привязка к данным через контекст данных ...

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I am trying to add a context menu to my WPF datagrid is specific to each row, because its items need to depend on the DataContext for that row.

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Он представляет собой простую реализацию команды WPF. Теперь для ... RowStyle>

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